π Split or Steal
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
Roleplaying as Ron to find Ronβs underlines (best responses)
If Cathy plays Split, what is Ronβs best response?
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
If Cathy plays Steal, what is Ronβs best response?
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
Roleplaying as Cathy to find Cathyβs underlines (best responses)
If Ron plays Split, what is Cathyβs best response?
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
If Ron plays Steal, what is Cathyβs best response?
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
Summarizing all of this in a single game grid, we get:
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
There are three Nash Equilibria:
- β(Ron β Steal, Cathy β Split)
- (Ron β Steal, Cathy β Steal)
- (Ron β Split, Cathy β Steal)
Why is the following strategy profile a Nash Equilibrium for poor Cathy:
β(Ron β Steal, Cathy β Split)It is a NE because Cathy canβt do any better than she already is.
Right now, we are in the bottom left box:
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
You might think that because Cathy has a payoff of $0, that this wouldnβt be an equilibrium for her. However, we will find that she canβt do anything at all to get a payoff of more than $0. Sheβs stuck.
Cathy only controls the column that we are in. She can choose whether she steals, but not whether Ron steals.
Her only option to deviate from this Nash Equilibrium is the decide to steal herself. If she decides to steal herself, she would get a payoff of $0. Thatβs not an improvement. She might be deviating, but is isnβt profitable.
Economists will often define NE as βA strategy profile (a list of what all players are doing), where no player can profitably deviate.β We have just verified that even though Cathy may be unhappy, she can not profitably deviate.
Because Cathy canβt control Ron, it is a best response for her to play Split when Ron plays Steam. In other words, she canβt profitably deviate.
In the split or steal game, for both players, it is a βweakly dominant strategyβ to steal. This means that it is never worse to steal, but it isnβt always better to steal. For regular dominant strategy, just βnot being worseβ isnβt good enough. It must actually better.)
For example, letβs confirm that stealing is weakly dominant for Ron.
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
If cathy is going to split, is it better for Ron to Steal? YES.
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
If Cathy is going to steal, is it better for Ron to Steal?
| Cathy β Split | Cathy β Steal | |
|---|---|---|
| Ron β Split | R=$20k, C=$20k | R=$0, C=$40K |
| Ron β Steal | R=$40K, C=$0 | R=$0, C=$0 |
Itβs definitely not worse!!
Because itβs not worse for Ron to choose steal, independent of what Cathy does, Stealing is a weakly dominant strategy for Ron.
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