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✏️ Formula Example

✏️ TC=3q2+5q+20TC = 3q^2 + 5q + 20
MC=6q+5MC = 6q + 5
P=20P = 20
What is profit?

✔ Click here to view answer

We know that we have to do the same three steps that we covered on Thursday..

Three steps: 1. Use MR=MC or P=MC to find q*. 2. Shut down if P is less than AVC when you produce q*. 3. Complete rest of problem, profit = q x (P-AC)

Step 1: The first step is setting P=MCP = MC, as you note. We can do this with our equations…
P=20P = 20
MC=6q+5MC = 6q + 5
P=MC20=6q+5P = MC \rightarrow 20 = 6q + 5
We can then use algebra to solve for the q which will make P=MCP = MC.
15=6q15 = 6q
q=156=2.5q = \frac{15}{6} = 2.5
Therefore, q=2.5q^* = 2.5

Step 2: Is P<AVCP < AVC. TC=3q2+5q+20TC = 3q^2 + 5q + 20, so VC=3q2+5qVC = 3q^2 + 5q, and
AVC=VCq=3q2+5qq=3q+5AVC = \frac{VC}{q} = \frac{3q^2 + 5q}{q} = 3q + 5
When q=2.5q^* = 2.5, then AVC=3×2.5+5=12.5AVC = 3 \times 2.5 + 5 = 12.5
P=20>AVC=12.5P = 20 > AVC = 12.5, so we don’t shut down. We produce q=q=2.5q = q^* = 2.5.

Step 3: Profit=q(PAC)=2.5×(20\text{Profit} = q^*(P - AC) = 2.5 \times (20 -
TC=3q2+5q+20=3×(2.5)2+5×2.5+20=51.25TC = 3q^2 + 5q + 20 = 3 \times (2.5)^2 + 5 \times 2.5 + 20 = 51.25
ATC=TCq=51.252.5=20.5ATC = \frac{TC}{q} = \frac{51.25}{2.5} = 20.5
Profit=q(PAC)=2.5×(2020.5)=1.25\text{Profit} = q^*(P - AC) = 2.5 \times (20 - 20.5) = -1.25
I won’t shut down, but I’ll be losing money, so I exit in the long run.  ✅

🙋 Can you tell us what happens in the long run and the short run?

✔ In the short run, your fixed costs are fixed. You are are stuck paying them.
TC=3q2+5q+20TC = 3q^2 + 5q + 20
In the short run, you must pay $20 of fixed costs. I like using the example (just for developing intuition) of the fixed cost being a lease. So let’s assume you have a $20 lease.

In the short run, if you produce qq^*, your profit is -1.25.
In the short run, if you produce 0 (shut down), then:
profit=TRTC=$0(30×02+5×0+20)=$0(30×02+5×0+20)=20\text{profit} = TR - TC = \$0 - (30 \times 0^2 + 5 \times 0 + 20) = \$0 - (30 \times 0^2 + 5 \times 0 + 20) = -20
Clearly, in the short run it is optimal to produce q=2.5q^* = 2.5

In the long run, you can also exit. If you exit, q=0q = 0, TR=0TR = 0, TC=0TC = 0, and profit=0\text{profit} = 0, because your firm doesn’t exist.
Now you have three options.
if you produce qq^*, your profit is -1.25.
if you produce 0 (shut down), your profit = -20
If you exit, your profit = $0 - $0 = $0.
Clearly, exiting is the best! In the long run, it wouldn’t be optimal to stay in business and produce qq^*. Rather, it would be optimal to exit. Exiting is like shutting down because q=0q = 0, but it is different because you have no costs at all (your firm doesn’t exist).

Therefore, the firm would just keep on producing q=2.5q = 2.5 units per year until the end of the short run (ie until the lease expires). Then it would exit and produce 0.  ✅