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✏️ Budget Constraint Exercises

✏️ Suppose that you have a food budget of $90. Chickens cost $9 and lettuce costs $3.
Putting chicken on the vertical axis and lettuce on the horizontal, draw your budget constraint:

✏️ Suppose that the price of chicken drops to $5. How will the budget constraint move?

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If the price of chicken drops to $5, then you will be able to afford $90$5=18 chickens\frac{\$90}{\$5} = 18\text{ chickens}, so the budget line will rotate upwards .  ✅

✏️ What happens to slope if both prices double?

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Nothing. The slope of the BC will not change because Slope Of BC =PxPy=\frac{P_x}{P_y}. If both prices double, then
Slope Of BC =2Px2Py= \frac{2P_x}{2P_y}
The 2s will cancel out, and you’ll be left with PxPy\frac{P_x}{P_y}. This budget constraintshows prices of $5 × 2 = $10 for chicken and $6 for lettuce, along with a budget of $90.  ✅

✏️ What happens if both prices double and your income also doubles?

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Previously, PCh=5P_{Ch}=5 and PL=3P_L=3. B=90B=90
Y Intercept =905=18\text{Y Intercept }= \frac{90}{5} = 18
X Intercept =903=30\text{X Intercept }= \frac{90}{3} = 30
Now, everything has doubled,
Y Intercept =90×25×2=905=18\text{Y Intercept }= \frac{90 × 2}{5 × 2} = \frac{90}{5} = 18
X Intercept =90×23×2=903=30\text{X Intercept }= \frac{90 × 2}{3 × 2} = \frac{90}{3} = 30  ✅

✏️ Suppose that your budget constraint is the green line given in the diagram below. Your budget is $20,000. What are PxP_x and PyP_y? For extra practice, you can repeat the exercise for the orange line.

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If B=$20K, with the green line, and the maximum number of good Y you can purchase with your budget, B is 20 Y, then

20×PY=$20K, so PY=$1K20 × P_Y = \$20\text{K, so }P_Y = \$1\text{K}

If the maximum of X you can purchase is 10, then 10×PX=$20K10 × P_X = \$20\text{K}, so PX=$2KP_X = \$2\text{K}

With the orange line, the maximum number of good Y you can purchase is 5 Y, then

5×PY=$20K, so PY=$4K5 × P_Y = \$20\text{K, so }P_Y = \$4\text{K}

If the maximum of X you can purchase is 25, then 25×PX=$20K25 × P_X = \$20\text{K}, so PX=$800P_X = \$800  ✅